How do you find the y intercept for $y = x^{2} - 4 x + 4$ $y = x^2 - 4x + 4$ ?

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Answer 1 · 2015-09-28T00:01:51

The y-intercept is $4$ $4$ .

The y-intercept is the value of $y$ $y$ when $x = 0$ $x=0$ . Therefore, substitute $0$ $0$ for $x$ $x$ , and solve for $y$ $y$ .

$y = x^{2} - 4 x + 4$ $y=x^2-4x+4$

$y = 0^{2} - 4 (0) + 4 =$ $y=0^2-4(0)+4=$

$y = 4$ $y=4$ .

Answer 2 · 2015-09-28T00:06:05

Y intercept is 4.

To find the Y-intercept, find the value of this function at $x = 0$ $x=0$

$y = x^{2} - 4 x + 4$ $y=x^2−4x+4$
At $x = 0; y = (0^{2}) - (4.0) + 4 = 4$ $x=0; y =(0^2)-(4.0)+4 = 4$

At $(0, 4)$ $(0, 4)$ the curve cuts the Y-axis.

How do you find the y intercept for y = x^2 - 4x + 4y=x2−4x+4y = x^2 - 4x + 4?