How do you find the zeroes for $y = {(x + 5)}^{2}$ $y=(x+5)^2$ ?

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How do you find the zeroes for $y = {(x + 5)}^{2}$ $y=(x+5)^2$ ?

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Answer 1 · 2015-07-08T09:34:32

There is a double root (zero) at x=-5

Explanation:

You have the equation factorised, it's trivial to see plugging in x=-5 results in y=0. The root is a double one because of the squared term, meaning the derivative (dy/dx - if you have reach calculus yet) is also zero at that point.

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How do you find the zeroes for $y = {(x + 5)}^{2}$ $y=(x+5)^2$ ?

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