Question

How do you find the zeroes of `f(x)=x^2+25`?

Answer 1

`x=5i`

Explanation:

Given: `f(x)=x^2+25`.

The zeroes of `f(x)` are values for `x` such that `f(x)=0`.

So we have:

`x^2+25=0`

`x^2=-25`

`x=sqrt(-25)`

`x=5i`