How do you find the zeroes of g(x)=2x^2-5x-3 ?

1 Answer
Alan P.
Jun 7, 2015

g(x) = 2x^2 -5x-3can be factored as
color(white)("XXXX")g(x)=(2x+1)(x-3)

The zeroes of g(x) are the values of x for which g(x)=0

If g(x) = (2x+1)(x-3) = 0 then
either
color(white)("XXXX")2x+1 = 0 rArr x= -1/2
or
color(white)("XXXX")x-3 = 0 rArr x = 3

So the zeros of g(x) are (-1/2) and 3

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