How do you find the zeros of $f (x) = x^{2} - 5 x - 6$ $f(x)=x^2-5x-6$ by factoring?

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Answer 1 · 2016-11-03T11:47:23

Zeros of the function $f (x)$ $f(x)$ are $x = 6 * and * x = - 1$ $x=6 **and** x = -1$

$f(x)=x^2-5x-6 = (x-6)(x+1)=0 :. (x-6)=0 or (x+1)=0$
So Zeros of the function are $x=6 and x = -1$ [Ans]

How do you find the zeros of f(x)=x^2-5x-6f(x)=x2−5x−6f(x)=x^2-5x-6 by factoring?