How do you find three consecutive even integers such that the sum of twice the first and third is 40?

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Answer 1 · 2018-07-02T07:45:47

#x=38/3#

Three consecutive numbers means #x#, #x+1#, #x+2#.

Twice the first means #2x#, the third is #x+2#

Sum them and equal #40#:

#2x+x+2=40#

#3x+2=40#

#3x=38#

#x=38/3#