Question

How do you find three consecutive integers whose sum is 108?

Answer 1

`35, 36, 37`

Explanation:

Suppose the second integer is `n`. Then the first and third are `n-1` and `n+1`:

`108 = (n-1) + n + (n+1) = 3n`

Dividing both ends by `3` we find:

`n = 36`

So the three integers are:

`35, 36, 37`