How do you find three consecutive odd integers whose sum is 117?

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Answer 1 · 2016-03-01T16:03:23

37, 39, 41

Three odd consecutive numbers can be written as x, x+2, and x+4.

Adding these together and setting to the answer we want, we get:
x + x + 2 + x + 4 = 117
Simplifying: 3x+6 = 117
3x = 111
x = 37

Now we find the next two odd numbers by adding 2 and 4 to this number.
37 + 2 = 39
37 + 4 = 41

So your answer is 37, 39 and 41.