How do you graph 1 + 2sin(2x - pi)1+2sin(2xπ)?

1 Answer
Jun 7, 2018

As detailed.

Explanation:

Standard form of sinusoidal function is y = A sin (Bx -C) + Dy=Asin(BxC)+D

Given y = 2 sin (2x - pi) + 1y=2sin(2xπ)+1

A = 2, B = 2, C = pi, D = 1A=2,B=2,C=π,D=1

Amplitude = |A| = 2Amplitude=|A|=2

"Period " = (2pi) / |B| = (2pi)/2 = piPeriod =2π|B|=2π2=π

"Phase Shift " = -C / B = pi/2Phase Shift =CB=π2, color(red)(pi/2 " to the right"π2 to the right

"Vertical Shift " = D = 1Vertical Shift =D=1

graph{2 sin(2x -pi) + 1 [-10, 10, -5, 5]}