How do you graph 10x>=10/3# on the coordinate plane?

1 Answer
Aug 22, 2017

See a solution process below:

Explanation:

First, we can solve for #x# by multiplying each side of the inequality by #color(red)(1/10)# which will also keep the inequality balanced:

#color(red)(1/10) xx 10x >= color(red)(1/10) xx 10/3#

#10/10x >= color(red)(1/color(black)(cancel(color(red)(10)))) xx color(red)(cancel(color(black)(10)))/3#

#1x >= 1/3#

#x >= 1/3#

To graph this inequality we draw a vertical line at the #1/3# point on the #x#-axis.

The line will be a solid line because the inequality operator has a "or equal to" clause.

We wil shade to the right of the line because the inequality operator has a "greater than" clause:

graph{x>=1/3 [-8, 8, -4, 4]}