How do you graph 10x>=10/3# on the coordinate plane?

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Answer 1 · 2017-08-22T00:41:58

See a solution process below:

First, we can solve for $x$ by multiplying each side of the inequality by $color(red)(1/10)$ which will also keep the inequality balanced:

$color(red)(1/10) xx 10x >= color(red)(1/10) xx 10/3$

$10/10x >= color(red)(1/color(black)(cancel(color(red)(10)))) xx color(red)(cancel(color(black)(10)))/3$

$1x >= 1/3$

$x >= 1/3$

To graph this inequality we draw a vertical line at the $1/3$ point on the $x$ -axis.

The line will be a solid line because the inequality operator has a "or equal to" clause.

We wil shade to the right of the line because the inequality operator has a "greater than" clause:

graph{x>=1/3 [-8, 8, -4, 4]}