How do you graph #2x+3y>4# on the coordinate plane?

1 Answer
Mar 31, 2018

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Explanation:

Move the #2x# to the other side to get #3y> -2x+4#. Then divide by 3 to get #y> -2/3x+4/3#. From here, graph the line #y=-2/3x+4/3#. Then shade in the area which satisfies the inequality (called a half-plane because its area is half of the area of the entire plane). Also, make the line a dotted line to show that it is not included.