How do you graph 2x-3y<=62x−3y≤6?

1 Answer
Meave60
Apr 22, 2015

Solve 2x-3y<=62x−3y≤6 for y.

Subtract 2x from both sides.

-3y<=-2x+6−3y≤−2x+6

Divide both sides by -3. This will reverse the <=≤ symbol to >=≥.

y>=-2/-3x-6/3y≥−2−3x−63=

y>=2/3x-2y≥23x−2

Determine two points on the line by using the equation making y=2/3-2y=23−2.

If x=0, y=2/3*0-2=0-2=-2x=0,y=23⋅0−2=0−2=−2 Point = (0,-2)(0,−2)
If x=3, y=2/cancel3*cancel3-2=2-2=0 Point = (3,0)

Plot the two points and draw a straight line through them. Then shade in the area above the line.
graph{y>=2/3x-2 [-10, 10, -5, 5]}

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