How do you graph 2x + 3y =-62x+3y=6 by plotting points?

1 Answer
Jun 15, 2018

"see explanation"see explanation

Explanation:

"one way is to find the intercepts, that is where the graph"one way is to find the intercepts, that is where the graph
"crosses the x and y axes"crosses the x and y axes

• " let x = 0, in the equation for y-intercept" let x = 0, in the equation for y-intercept

• " let y = o, in the equation for x-intercept" let y = o, in the equation for x-intercept

x=0rArr0+3y=-6rArry=-2larrcolor(red)"y-intercept"x=00+3y=6y=2y-intercept

y=0rArr2x+0=-6rArrx=-3larrcolor(red)"x-intercept"y=02x+0=6x=3x-intercept

"plot the points "(0,-2)" and "(-3,0)plot the points (0,2) and (3,0)

"draw a straight line through them for graph"draw a straight line through them for graph
graph{(y+2/3x+2)((x-0)^2+(y+2)^2-0.04)((x+3)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}