How do you graph $- 2 x + 3 y > 9$ $-2x+3y>9$ ?

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Answer 1 · 2016-11-23T05:16:31

Graph $- 2 x + 3 y > 9$ $-2x+3y>9$

Convert the inequality to slope-intercept form, by solving for $y$ $y$ .

Add $2 x$ $2x$ to both sides.

$3 y > 2 x + 9$ $3y>2x+9$

Divide both sides by $3$ $3$ .

$y > \frac{2}{3} x + \frac{9}{3}$ $y>2/3x+9/3$

Simplify.

$y > \frac{2}{3} x + 3$ $y>2/3x+3$

Determine two points on the line.

$x = 0 :$ $x=0:$ $y = 3$ $y=3$

$y = 0 :$ $y=0:$ $x = - \frac{9}{2}$ $x=-9/2$

Plot the points.

Draw a dashed straight line to indicate that the line is not part of the inequality.

Shade in the area above the line.

graph{y>2/3x+3 [-10, 10, -5, 5]}

How do you graph -2x+3y>9−2x+3y>9-2x+3y>9?