How do you graph 2x – 4y > 8 and y <3x + 1?

1 Answer
Nov 5, 2017

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Explanation:

to get the intersections with the coordinate axes
for with the x axis y=0

2x-4y=8
when y=0
2x=8
x=4
then is the point (4,0)

now with the y axis, x=0
when x=0

2x-4y=8
-4y=8
y=-2
then is the point (0;-2)

then both points are located and the straight line is obtained
by being an inequality and having the greater sign, a line segment and shaded down is graphed

now y<3x+1

same for y=0

0<3x+1
-1/3=x

for x=0

y<1
y=1

it can also write as 3x+1>y by being an inequality and having the greater sign, a line segment and shaded down is graphed