How do you graph $- 2 x - y < 4$ $-2x-y<4$ on the coordinate plane?

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Answer 1 · 2017-05-03T20:40:45

$x >$ $x>$ $- \frac{y}{2} - 2$ $-y/2-2$

$- 2 x - y < 4$ $-2x-y<4$

add y to both sides:

$- 2 x <$ $-2x<$ $y + 4$ $y+4$

divide both sides by $- 2$ $-2$ . be sure to flip the sign because youre dividing by a negative number:

$x >$ $x>$ $- \frac{y}{2} - 2$ $-y/2-2$

to graph the inequality, you can plug in any x value to find the matching y value. For example:

$- 2 (1) - y < 4$ $-2(1)-y<4$
$y >$ $y>$ $- 6$ $-6$
$(1, - 6)$ $(1,-6)$

$- 2 (7) - y < 4$ $-2(7)-y<4$
$y >$ $y>$ $- 18$ $-18$
$(7, - 18)$ $(7,-18)$

you can use the points to find the line of inequality.
graph{x>(-y/2)-2 [-32.66, 3 2.67, -16.33, 16.33]}

How do you graph -2x-y<4−2x−y<4-2x-y<4 on the coordinate plane?