Question

How do you graph `3 < -2y+6x`?

Answer 1

Graph `3 < -2y + 6x`

Explanation:

Standard form of a linear function in 2 variable:
-2y + 6x - 3 > 0
First, graph Line: - 2y + 6x - 3 = 0 by its intercepts.
Make x = 0 -> y = 1/2. Make y = 0 -> x = - 3/2.
To find the solution set area, use origin O as test point. Substitute x = 0 and y = 0 into the inequality, we get -3 > 0. Not true. Then, the solution set area doesn't contain the origin O. The solution set is the area below the line. Color this answer.
Graph graph{- 2y + 6x - 3 = 0 [-10, 10, -5, 5]}