Question

How do you graph `3q+7>=13`?

Answer 1

First graph `y=3q+7` by choosing two conventient `q`'s and calculating the corresponding `y`'s (`q=0` is allways a good choice). Then draw a line through them. Also draw the horizontal line at `y=13`. Everywhere the first line is on or above the `13`-mark is a solution (answer: `q>=2`)
graph{3x+7 [-31.4, 33.57, -6.62, 25.85]}