How do you graph $3x + 1 < -35$ and $-2/3x <=6$ ?

Question

1362 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-07-25T14:34:16

Solve system:
(1) $3x + 1 < - 35$
(2) $-2x/3 <= 6$

(1) --> 3x < -36 --> x < -12

(2) x >= -18/2 --> x > -9

===========|-12-------------|-9==========|0========

NOTE. The critical point (-9) is included in the solution set.
Answer by intervals: (-infinity, -12) and [-9, +infinity)

How do you graph 3x + 1 < -353x + 1 < -35 and -2/3x <=6 -2/3x <=6?