How do you graph $3x+2>2, 3x<=6$ ?

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Answer 1 · 2017-05-23T20:30:33

See below.

$3x+2>2$

Subtract both sides of the equation by 2

$3x>0$

Divide both sides of the equation by 3

$x>0$

graph{x>0 [-10, 10, -5, 5]}

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$3x <= 6$

Divide both sides of the equation by

$x <= 2$ graph{x<=2 [-10, 10, -5, 5]}

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The answer is where these 2 graphs overlap.

How do you graph 3x+2>2, 3x<=63x+2>2, 3x<=6?