How do you graph $3 x + 2 y = 6$ $3x+2y=6$ by plotting points?

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Answer 1 · 2018-05-22T19:19:07

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$ $x = 0$

$(3 \cdot 0) + 2 y = 6$ $(3 * 0) + 2y = 6$

$0 + 2 y = 6$ $0 + 2y = 6$

$2 y = 6$ $2y = 6$

$\frac{2 y}{2} = \frac{6}{2}$ $(2y)/color(red)(2) = 6/color(red)(2)$

$y = 3$ $y = 3$ or $(0, 3)$ $(0, 3)$

Second Point: For $y = 0$ $y = 0$

$3 x + (2 \cdot 0) = 6$ $3x + (2 * 0) = 6$

$3 x + 0 = 6$ $3x + 0 = 6$

$3 x = 6$ $3x = 6$

$\frac{3 x}{3} = \frac{6}{3}$ $(3x)/color(red)(3) = 6/color(red)(3)$

$x = 2$ $x = 2$ or $(2, 0)$ $(2, 0)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-3)^2-0.035)((x-2)^2+y^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(3x + 2y - 6)(x^2+(y-3)^2-0.035)((x-2)^2+y^2-0.035)=0 [-10, 10, -5, 5]}

How do you graph 3x+2y=63x+2y=63x+2y=6 by plotting points?