How do you graph 3x-5y= 10 using the slope and y intercept?

1 Answer
Feb 5, 2015

You first work this into a standard form y=ax+b

Step 1: x's to the right:
3x-5y=10->-5y=-3x+10

Step 2: divide everything by -5 to get the y
(-5y)/(-5)=(-3x)/(-5)+10/(-5)->y=3/5 x-2

Now your slope is 3/5 and your y-intercept is -2

Graphing:
One point is (0,-2), the y-intercept
Take any x-value and plug it in the equation, let's say 5
this gives you y=3/5 *5-2=1, so (5,1)
Draw the line:
graph{0.6x-2 [-10, 10, -5, 5]}