How do you graph 3x-5y= 103x5y=10 using the slope and y intercept?

1 Answer
Feb 5, 2015

You first work this into a standard form y=ax+by=ax+b

Step 1: xx's to the right:
3x-5y=10->-5y=-3x+103x5y=105y=3x+10

Step 2: divide everything by -55 to get the yy
(-5y)/(-5)=(-3x)/(-5)+10/(-5)->y=3/5 x-25y5=3x5+105y=35x2

Now your slope is 3/535 and your yy-intercept is -22

Graphing:
One point is (0,-2)(0,2), the yy-intercept
Take any xx-value and plug it in the equation, let's say 55
this gives you y=3/5 *5-2=1y=3552=1, so (5,1)(5,1)
Draw the line:
graph{0.6x-2 [-10, 10, -5, 5]}