How do you graph -3x+5y< -253x+5y<25?

1 Answer
Jul 10, 2017

Graph:

-3x+5y<-253x+5y<25

Find the x and y-intercepts by setting x=0x=0 and y=0y=0.

X-intercept

y=0y=0

-3x+5(0)<-253x+5(0)<25

-3x<-253x<25

Divide both sides by -33.

x<25/3x<253

x<8 1/3x<813

x-intercept: (25/3,0)(253,0) or (8 1/3,0)(813,0)

Y-intercept

x=0x=0

-3(0)+5y<-253(0)+5y<25

5y<-255y<25

Divide both sides by 55.

y=-5y=5

y-intercept: (0,-5)(0,5)

You now have two points on the line. Plot the points and draw a dashed line through them to indicate that the line is not part of the inequality. Shade in the area below the line to indicate the inequality.

graph{-3x+5y<-25 [-16.02, 16.01, -8.01, 8.01]}