How do you graph $3x - y < 4$ ?

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Answer 1 · 2018-08-01T05:37:59

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Please read the explanation.

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How do we graph $color(red)(3x-y<4$

Subtract $color(blue)(3x$ from both sides of the inequality

$3x-y-3x<4-3x$

$cancel (3x)-y-cancel(3x)<4-3x$

$-y<4-3x$

Multiply both the sides of the inequality by $color(blue)((-1)$

Remember to reverse the inequality.

$(-1)(-y)>(-1)(4-3x)$

$y > -4+3x$

$y>3x-4$

Now we can graph this simple inequality:

enter image source here

The dotted line indicates value that is NOT part of the solution.

Hope it helps.

How do you graph 3x - y < 43x - y < 4?