How do you graph 4x-2y>20?

1 Answer
Mar 20, 2018

See a solution process below:

Explanation:

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.

For: x = 0

(4 * 0) - 2y = 20

0 - 2y = 20

-2y = 20

(-2y)/color(red)(-2) = 20/color(red)(-)

y = -10 or (0, -10)

For: y = 0

4x - (2 * 0) = 20

4x - 0 = 20

4x = 20

(4x)/color(red)(4) = 20/color(red)(4)

x = 5 or (5, 0)

We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.

graph{(x^2+(y+10)^2-0.25)((x-5)^2+y^2-0.25)(4x-2y-20)=0 [-30, 30, -15, 15]}

Now, we can shade the right side of the line.

The boundary line will be changed to a dashed line because the inequality operator does not contain an "or equal to" clause.

graph{(4x-2y-20) > 0 [-30, 30, -15, 15]}