Question

How do you graph `6x>=-1/3y` on the coordinate plane?

Answer 1

See explanation

Explanation:

Given: `6x >= -1/3y`

Multiply both sides by (-1 )

`-6x <= 1/3ycolor(white)("dd")` Notice that the inequality has turned round.

Multiply both sides by 3

`-18x<=y`

Now plot the straight line graph of `y=-18x`

Draw any vertical line. `y` can and may take on any value above and on `y=-18x`

Example: suppose I pick on `x= 1/2` Then the brown line in the graph below represents all the feasible values for `y` at `x=1/2`

Lots and lots of these lines, when combined, give an 'area' on the graph (as shaded) that represents all the possible values of `y` for all the possible values of `x`.