How do you graph and label the vertex and axis of symmetry $y=1/2x^2+4x+10$ ?

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Answer 1 · 2017-11-29T13:14:41

Refer to the graph available with this answer.

We have the quadratic equation

$y = (1/2)x^2 + 4x +10$

Axis of Symmetry is given by $(-b)/(2a)$

So, for our quadratic, Axis of Symmetry = $(-4)/((2*(1/2))$ ,
which gives us $(-4)$

Substitute this value of Axis of Symmetry in our original equation to obtain the Vertex.

$y = (1/2)(-4)^2 + 4(-4) + 10$

$y = (1/2)16 -16 + 10$

$y = 2$

So, our Vertex is at $(-4, 2)$

Refer to the labeled graph attached with Vertex and Axis of Symmetry identified.
enter image source here

How do you graph and label the vertex and axis of symmetry y=1/2x^2+4x+10y=1/2x^2+4x+10?