Question

How do you graph and state the max/min for `f(x) = 3x^2 + 4x - 5`?

Answer 1

Graph `f(x) = 3x^2 + 4x - 5`.

Explanation:

The graph is a parabola that opens upward `(a > 0)`.
There is a minimum at vertex,
`x`- coordinate of vertex: `x = -b/(2a) = -4/6 = -2/3`.
`y`-coordinate of vertex: `y = f(-2/3) = 3(4/9) - 8/3 - 5 = 12/9 - 24/9 - 45/9 = (-57/9)`
graph{3x^2 + 4x - 5 [-20, 20, -10, 10]}