How do you graph $f(x)= 2x^2+8x+7$ ?

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Answer 1 · 2015-09-08T10:39:58

Refer explanation section

find the vertex

$x=(-b)/(2a)=(-8)/(2 xx 2)=-2$
$x: y$
$-5 :17$
$-4: 7$
$-3 :1$
$-2 :-1$
$-1 :1$
$0 :7$
$1 :17$

Take a few values on either side of x, plot the points and draw a smooth curve. graph{2x^2 +8x+7 [-22.82, 22.81, -11.4, 11.4]}

How do you graph f(x)= 2x^2+8x+7f(x)= 2x^2+8x+7?