How do you graph $f(x) = 4 cos(x - pi/2 ) + 1$ ?

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Answer 1 · 2018-07-16T02:06:22

As below.

Standard form of a cosine function is $f(x) = A cos (Bx - C) + D$

$"Given : " f(x) = 4 cos (x - pi/2) + 1$

$A = 4, B = 1, C = pi/2, D = 1$

$"Amplitude " = |A| = 4$

$"Period " = (2 pi) / |B| = 2pi$

$"Phase Shift " = -C / B = -(pi/2) / 1 = -pi/2, color(red)(pi/2 " to the LEFT"$

$"Vertical Shift " = D = 1$

graph{4 cos(x - pi/2) + 1 [-10, 10, -5, 5]}

How do you graph f(x) = 4 cos(x - pi/2 ) + 1f(x) = 4 cos(x - pi/2 ) + 1?