How do you graph $f(x)=-cos(x/2)$ ?

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Answer 1 · 2018-06-07T07:17:55

As detailed.

$f(x) = - cos (x/2)$

Standard form $y = A cos (Bx - C) + D$

$A = -1, B = 1/2, C = D = 0$

$Amplitude = |A| = 1$

$"Period " = (2pi) / |B| = (2pi) / (1/2) = 4pi$

$"Phase Shift " = -C / B = 0$

$"Vertical Shift " = D = 0$

graph{-cos (x/2) [-10, 10, -5, 5]}

How do you graph f(x)=-cos(x/2)f(x)=-cos(x/2)?