How do you graph $f (x) = cos (x - 30)$ $f(x)=cos(x-30)$ ?

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Answer 1 · 2018-06-26T06:24:47

As below.

$Standard form of cosine function is f (x) = A cos (B x - C) + D$ $"Standard form of cosine function is " f(x) = A cos (Bx - C) + D$

$Given : f (x) = cos (x - 30^{\circ}) = cos (x - \frac{π}{6})$ $"Given : " f(x) = cos (x - 30^@) = cos (x - pi/6)$

$A = 1, B = 1, C = \frac{π}{3}, D = 0$ $A = 1, B = 1, C = pi/3, D = 0$

$Amplitude = | A | = 1$ $"Amplitude " = |A| = 1$

$Period = \frac{2 π}{| B |} = 2 π$ $"Period " = (2pi) / |B| = 2pi$

$Phase Shift = - \frac{C}{B} = - \frac{π}{3}, \frac{π}{3} to the LEFT$ $"Phase Shift " = -C / B = -pi/3, " " color(crimson)(pi/3 " to the LEFT"$

$Vertical Shift = D = 0$ $"Vertical Shift " = D = 0$

graph{cos (x - pi/6) [-10, 10, -5, 5]}

How do you graph f(x)=cos(x−30)f(x)=cos(x-30)?