How do you graph f(x)= (x^2-100)/(x+10)f(x)=x2100x+10?

1 Answer
Jun 28, 2015

f(x) = (x^2-100)/(x+10) = ((x-10)(x+10))/(x+10) = x-10f(x)=x2100x+10=(x10)(x+10)x+10=x10

with excluded value x=-10x=10.

This is a straight line of slope 11 passing through (0, -10)(0,10) and (10, 0)(10,0) with excluded point (-10, -20)(10,20)

Explanation:

f(x) = (x^2-100)/(x+10)f(x)=x2100x+10

= ((x-10)(x+10))/(x+10)=(x10)(x+10)x+10

= x-10=x10

with exclusion x!=-10x10.

The graph of f(x)f(x) is like the graph of x-10x10 except that f(x)f(x) is not defined at the point (-10, -20)(10,20)

All the limits as you approach that point behave well, it's just that f(-10)f(10) is undefined as it's equal to 0/000.

graph{(x^2-100)/(x+10) [-37.5, 42.5, -24, 16]}