Question

How do you graph `g(x) = (x+3)(x+2)`?

Answer 1

The x-intercepts are at `x=-3` and `x=-2`
The vertex is at `(-2.5,-0.25)`
Pick a few more points and connect to form graph.

Explanation:

If `g(x)=(x+3)(x+2)`
then when `g(x)=0` either `x=-3` or `x=-2`

Since this is a parabola in standard position,
the vertex will be midway between the x-intercepts
i.e. at `x=-2.5`
and `g(-2.5) = 0.25`

You could pick a few more random point; for example:
`x=0color(white)("XXXX")rarrcolor(white)("XX")g(0)=6`
`x=-4color(white)("XX")rarrcolor(white)("XX")g(-4)=2`

graph{(x+3)(x+2) [-7.033, 4.067, -1, 4.55]}