How do you graph $h(x) = 2 sin(πx−3π) − 4$ ?

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Answer 1 · 2018-06-07T07:22:50

As below.

$h(x) = 2 sin (pi x - 3pi) - 4$

Standard form is $y = A sin (Bx - C) + D$

$A = 2, B = pi, C = 3pi, D = -4$

$Amplitude = |A| = 2$

$"Period " = (2pi) / |B| = (2pi) / pi = 2$

$"Phase Shift " = -C / B = (3pi) / pi = 3$ , $color(red)(3 " to the right"$

$"Vertical Shift " = D = -4$

graph{2 sin (pi x - 3pi) - 4 [-10, 10, -5, 5]}

How do you graph h(x) = 2 sin(πx−3π) − 4h(x) = 2 sin(πx−3π) − 4?