Question

How do you graph, label the vertex, axis of symmetry and x intercepts of `y=-1/2(x-3)(x+2)`?

Answer 1

The 2 x-intercepts are: x1 = 3 and x2 = - 2.
The x-coordinate of the axis of symmetry, and the vertex is:
`x = (x1 + x2)/2 = (3 - 2)/2 = 1/2`
y-coordinate of vertex:
`y(1/2) = - 1/2 (1/2 - 3)(1/2 + 2) = (-1/2)(-5/2)(5/2) = 25/8`
Vertex `(1/2, 25/8)`
graph{-1/2(x - 3)(x + 2) [-10, 10, -5, 5]}