Question

How do you graph `tan(x/2) + 1`?

Answer 1

graph{tan(x/2)+1 [-10, 10, -5, 5]}

Explanation:

You first have to know what the graph of `tan(x)` looks like

graph{tan(x) [-10, 10, -5, 5]}

It has vertical assymptotes at `pi` intervals so the period is `pi` and when x=0 y=0

So if you have `tan(x)+1` it shifts all the y values up by one

`tan(x/2)` is a vertical shift and it doubles the period to `2pi`

graph{tan(x/2)+1 [-10, 10, -5, 5]}