How do you graph the arithmetic sequence #a_n=4-1/2n#?

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Answer 1 · 2018-03-17T07:58:40

As below.

Given #a_n = 4 - (1/2)n#

#a_1 = 4 - 1/2 = 7/2#

#a_2 = 4 - (1/2) * 2 = 3#

#a_3 = 4 - (1/2) * 3 = 5/2#

#d = a_2 - a_1 = a_3 - a_2 = 1/2#

#y = mx + c#

Given equation is #y = -(1/2)n + 4#

where slope #m = -(1/2), y"-intercept" = 4#

graph{-(1/2)x + 4 [-10, 10, -5, 5]}