How do you graph the inequality #2x + 3y > 6#?

1 Answer
Bill K.
Apr 6, 2015

First draw a lightly dashed version of the line #2x+3y=6#, which is equivalent to #y=-\frac{2}{3}x+2# (a line with a slope of #-2/3# and a #y#-intercept of #y=2#...also note that the #x#-intercept is #x=3#).

Next, note that the point #(0,0)# does not satisfy the inequality #2x+3y>6#. Therefore, shade in the "half-plane" on the other side of the line #2x+3y=6# from the side that #(0,0)# is on. Make sure the line #2x+3y=6# remains lightly dashed. It's not part of the solution set.

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