How do you graph the inequality #2x + 3y> 6#?

1 Answer
Sep 17, 2016

Draw a dashed line and shade above the line.

Explanation:

Draw the straight line graph of #2x +3y =6#

Use the intercept method:

For the #x-#intercept, make #y=0 rarr 2x = 6 rarr x= 3#

For the #y-#intercept, make #x=0 rarr 3y = 6 rarr y= 2#

Now that you have the two intercepts you can draw the line.
However because the inequality sign #># is used, the line itself is not part of the solution, draw a dashed line, not a solid line.

To show the solution, you need to shade one side of the line.
In this case shade the wanted region.

To decide which side, test with the origin #(0,0)#

#2x +3y > 6#
#2(0) +3(0) > 6#

#0 > 0# is false, so #(0,0)# is NOT part of the solution.

Shade the area which does NOT include the origin.
(ie shade above the line) for the solution/