How do you graph the inequality 2x + 3y> 62x+3y>6?

1 Answer
Sep 17, 2016

Draw a dashed line and shade above the line.

Explanation:

Draw the straight line graph of 2x +3y =62x+3y=6

Use the intercept method:

For the x-xintercept, make y=0 rarr 2x = 6 rarr x= 3y=02x=6x=3

For the y-yintercept, make x=0 rarr 3y = 6 rarr y= 2x=03y=6y=2

Now that you have the two intercepts you can draw the line.
However because the inequality sign >> is used, the line itself is not part of the solution, draw a dashed line, not a solid line.

To show the solution, you need to shade one side of the line.
In this case shade the wanted region.

To decide which side, test with the origin (0,0)(0,0)

2x +3y > 62x+3y>6
2(0) +3(0) > 62(0)+3(0)>6

0 > 00>0 is false, so (0,0)(0,0) is NOT part of the solution.

Shade the area which does NOT include the origin.
(ie shade above the line) for the solution/