How do you graph the inequality $-3x < -6$ or $x + 5< -2$ ?

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Answer 1 · 2017-02-01T14:19:19

open intervals (- inf., -7) and (2, + inf.)

(1) - 3x < - 6 --> $x > (-6)/(-3) = 2$
(2) x + 5 < - 2 --> $x < - 7$

You may solve the linear compound inequalities by graphing, using the double-number-line technique:

(1) -------------------------------------- 0 ---------- 2 +++++++++++++++

(2) +++++ - 7-------------------------0 ---------------------------------------

By superimposing, we see the answer, that is the open intervals: (-inf., -7) and (2, +inf.)

How do you graph the inequality -3x < -6-3x < -6 or x + 5< -2 x + 5< -2 ?