How do you graph the inequality $3x-y<=6$ ?

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Answer 1 · 2017-05-26T02:43:14

See the explanation.

Graph:

$3x-y>=6$

Change the equation to the slope intercept form by solving for $y$ .

Subtract $3x$ from both sides.

$color(red)cancel(color(black)(3x))-color(red)cancel(color(black)(3x))-y>=6-3x$

Simplify.

$-y>=-3x+6$

Multiply both sides by $-1$ . This will change the direction of the inequality.

$y<=3x-6$

Determine some points on the line by picking values for $x$ and solving for $y$ .

Points
$x=-2,$ $y=-12$
$x=0,$ $y=-6$
$x=2,$ $y=0$

Plot the points, and draw a straight solid line through them. Then shade the area below the line.

Graph graph{y<=3x-6 [-15.7, 16.32, -13.07, 2.95]}

How do you graph the inequality 3x-y<=6 3x-y<=6 ?