How do you graph the inequality $5 y + 8 \leq 33$ $5y+8<=33$ on the coordinate plane?

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Answer 1 · 2017-02-18T08:17:49

The inequality simplifies to $y \leq 5$ $y <=5$

First write the equation with a single $y$ $y$ .

$5 y + 8 \leq 33 \to 5 y \leq 33 - 8 \to 5 y \leq 25$ $5y +8 <= 33" "rarr 5y <=33-8" "rarr 5y <=25$

The equation simplifies to $y \leq 5$ $y <=5$

All horizontal lines have the equation: $y ='a number'$ $y = " 'a number' "$

The inequality has a solid horizontal line and a shaded area below the line. (y can be equal to 5 as well as being a value less than 5.)

graph{y <= 5 [-20.88, 19.12, -10.36, 9.64]}

How do you graph the inequality 5y+8<=335y+8≤335y+8<=33 on the coordinate plane?