How do you graph the inequality $a + b<12$ ?

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Answer 1 · 2016-12-23T09:28:08

See below:

It will look like this:

graph{y<12-x [-20, 20, -15, 15]}

The shaded area is the solution.

The line has a slope of $-1$ , passes through the y axis at $y=12$ , and has a dotted line to indicate that the line itself is not a solution.

How do you graph the inequality a + b<12a + b<12?