How do you graph the inequality y + 2<= -2/3(x - 6).y+2≤−23(x−6).?

1 Answer
MeneerNask
Aug 30, 2016

You can rewrite the inequality in slope-intercept form:

Explanation:

First work away the parentheses:
y+2<=-2/3x-2/3(-6)->y+2≤−23x−23(−6)→
y+2<=-2/3x+4->y<=-2/3x+2y+2≤−23x+4→y≤−23x+2

If you graph the line of y=-2/3x+2y=−23x+2, the line itself and everything under it fits the inequality.

The yy-intercept will be x=0->(0,2)x=0→(0,2),
the xx-intercept will be y=0->(3,0)y=0→(3,0)
graph{-2/3x+2 [-10, 10, -5, 5]}

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