Question

How do you graph the inequality `y< -2/3x+1`, `y>4x-5`?

Answer 1

Any (x, y) in the shaded region on the LHS of the common point `(9/7, 1/7)`, sans the common point and the dotted lines, is a solution to the combined inequality..

Explanation:

The shaded region in the graph represents

`{y<-2/3x+1 and y > 4x-5}` and the reversed-opposite

`{y>-2/3x+1 and y < 4x-5}`.

Our solutions (x, y) are in the LHS of the common point `(9/7, 1/7)`,

sans the common point and the dotted lines..

Please ignore the part on the RHS.

graph{(y+2/3x-1)(y-4x+5)<0x^2 [-10, 10, -5, 5]}