How do you graph the inequality y< -2/5x+1y<25x+1?

1 Answer
Nov 2, 2015

The slope is -2/525.
The y-intercept is 11. The point is (0,1)(0,1).
The x-intercept is 2/525. The point is (2/5,0)(25,0).

Explanation:

y<-2/5x+1y<25x+1 is in the slope-intercept form of a linear equation, y=mx+by=mx+b, where mm is the slope and bb is the y-intercept. The y-intercept is the value of yy when xx is 00.

Find the xx and yy intercepts.

The y-intercept is +1+1.

The point for the y-intercept is (0,1)(0,1).

Find the xx intercept by substituting 00 for yy and solving for xx.

0=-2/5x+10=25x+1

Subtract 11 from both sides.

-1=-2/5x1=25x

Multiply both sides by 55

5xx-1=-2x5×1=2x

-5=-2x5=2x

Divide both sides by -22.

(-5)/(-2)=x52=x

5/2=x52=x

Switch sides.

x=5/2x=52

The x-intercept is 5/252.

The point for the x-intercept is (5/2,0)(52,0).

Plot the two points on a graph. Draw a straight dashed line through the points to indicate that the line is not part of the inequality. Then shade the area below the line.

graph{y<-2/5x+1 [-10, 10, -5, 5]}