How do you graph the inequality $y < (x-2)^2 + 2$ ?

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Answer 1 · 2016-03-18T16:56:51

Graph the parabola $(x-2)^2=y-2$ . Shade the region benearth this parabola. For any (x, y) here, $y<(x-2)^2+2$ .

The parabola has vertex at (2, 2) and axis, upward from here, along the line x = 2, parallel to y-axis,

How do you graph the inequality y < (x-2)^2 + 2y < (x-2)^2 + 2?