How do you graph the line $x + y = 3$ $x+y=3$ ?

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Answer 1 · 2018-04-12T01:34:23

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$ $x = 0$

$0 + y = 3$ $0 + y = 3$

$y = 3$ $y = 3$ or $(0, 3)$ $(0, 3)$

Second Point: For $y = 0$ $y = 0$

$x + 0 = 3$ $x + 0 = 3$

$x = 3$ $x = 3$ or $(3, 0)$ $(3, 0)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-3)^2-0.035)((x-3)^2+y^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(x + y - 3)(x^2+(y-3)^2-0.035)((x-3)^2+y^2-0.035)=0 [-10, 10, -5, 5]}

How do you graph the line x+y=3x+y=3x+y=3?