How do you graph the line y=-3x+3y=3x+3?

1 Answer
Dec 18, 2016

Wee explanation

Explanation:

color(blue)("Main Method :")Main Method :

Determine 2 separate points which are marked on the graph paper then draw a line through them.
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color(purple)("Method 1") Method 1

Substitute any sensible values into xx and se what value of yy you get. Then plot the points with a line going through them.

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color(purple)("Method 2 - more about teaching algebra")Method 2 - more about teaching algebra

color(blue)("Determine the point where "x=0)Determine the point where x=0

Substitute 0 wherever xx is

y=-3x+3" "->" "y=-3(0)+3y=3x+3 y=3(0)+3

but 0xx(-3)=00×(3)=0 giving:

y=0+3y=0+3

So at x=0" "yx=0 y takes on the value of 3

So point 1 ->P_1->(x,y)=(0,3)P1(x,y)=(0,3)
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color(blue)("Determine the point where "y=0)Determine the point where y=0

Substitute 0 wherever yy is:

y=-3x+3" "->" "0=-3x+3y=3x+3 0=3x+3

Add 3x3x to both sides

0+3x=-3x+3x+30+3x=3x+3x+3

but -3x+3x=03x+3x=0

3x=0+33x=0+3

Divide both sides by 3

3/3x=3/333x=33

But 3/3=133=1

x=1x=1

So point 2 ->P_2->(x,y)=(1,0)P2(x,y)=(1,0)
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Tony B